When I do this:
a=cut -c 25-31 <<< 'REFDV.UJH.c01r00.GLOBAL.2000.06.99.9999.MLM.10KM.ZZ00.MM1.00.nc'
I got echo a
2000.06
I would like to systematically return a as
01062000
always add 01 and arrange it differently
About linux : How-to-add-a-number-and-rearrange-a-date-in-linux
Question Detail
Question Answer
A more efficient approach might be to obtain and format the output in one operation using awk, i.e.
$ awk -F'.' '{ print "01"$6$5 }' <<< 'REFDV.UJH.c01r00.GLOBAL.2000.06.99.9999.MLM.10KM.ZZ00.MM1.00.nc'
01062000
$
If you want to save the output to a shell variable named a:
$ a=$(awk -F'.' '{ print "01"$6$5 }' <<< 'REFDV.UJH.c01r00.GLOBAL.2000.06.99.9999.MLM.10KM.ZZ00.MM1.00.nc')
$ echo "$a"
01062000
$
$ a='REFDV.UJH.c01r00.GLOBAL.2000.06.99.9999.MLM.10KM.ZZ00.MM1.00.nc'
$ d=$(echo $a | cut -d . -f 5-6 --output-delimiter=- | sed 's/\(.*\)/\1-01/')
$ echo $d
2000-06-01
$ date -d "$d" +%d%m%Y
01062000
$ date -d "$d" +%c
Thu 01 Jun 2000 12:00:00 AM CDT
You can try
year=`echo $a | cut -d '.' -f1 `
month=`echo $a | cut -d '.' -f2 `
echo "01$month$year"
[email protected]:~$ echo "01$month$year"
01062000